Optimal. Leaf size=439 \[ \frac{g^{3/2} \sqrt [4]{b^2-a^2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt{g} \sqrt [4]{b^2-a^2}}\right )}{a \sqrt{b} f}+\frac{g^{3/2} \sqrt [4]{b^2-a^2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt{g} \sqrt [4]{b^2-a^2}}\right )}{a \sqrt{b} f}+\frac{g^2 \left (a^2-b^2\right ) \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{g \cos (e+f x)}}+\frac{g^2 \left (a^2-b^2\right ) \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{g \cos (e+f x)}}-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{g^{3/2} \tanh ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{2 g^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \sqrt{g \cos (e+f x)}} \]
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Rubi [A] time = 1.13782, antiderivative size = 439, normalized size of antiderivative = 1., number of steps used = 21, number of rules used = 16, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.516, Rules used = {2898, 2565, 321, 329, 212, 206, 203, 2695, 2867, 2642, 2641, 2702, 2807, 2805, 208, 205} \[ \frac{g^{3/2} \sqrt [4]{b^2-a^2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt{g} \sqrt [4]{b^2-a^2}}\right )}{a \sqrt{b} f}+\frac{g^{3/2} \sqrt [4]{b^2-a^2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt{g} \sqrt [4]{b^2-a^2}}\right )}{a \sqrt{b} f}+\frac{g^2 \left (a^2-b^2\right ) \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \left (a^2-b \left (b-\sqrt{b^2-a^2}\right )\right ) \sqrt{g \cos (e+f x)}}+\frac{g^2 \left (a^2-b^2\right ) \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \left (a^2-b \left (\sqrt{b^2-a^2}+b\right )\right ) \sqrt{g \cos (e+f x)}}-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{g^{3/2} \tanh ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{2 g^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \sqrt{g \cos (e+f x)}} \]
Antiderivative was successfully verified.
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Rule 2898
Rule 2565
Rule 321
Rule 329
Rule 212
Rule 206
Rule 203
Rule 2695
Rule 2867
Rule 2642
Rule 2641
Rule 2702
Rule 2807
Rule 2805
Rule 208
Rule 205
Rubi steps
\begin{align*} \int \frac{(g \cos (e+f x))^{3/2} \csc (e+f x)}{a+b \sin (e+f x)} \, dx &=\int \left (\frac{(g \cos (e+f x))^{3/2} \csc (e+f x)}{a}-\frac{b (g \cos (e+f x))^{3/2}}{a (a+b \sin (e+f x))}\right ) \, dx\\ &=\frac{\int (g \cos (e+f x))^{3/2} \csc (e+f x) \, dx}{a}-\frac{b \int \frac{(g \cos (e+f x))^{3/2}}{a+b \sin (e+f x)} \, dx}{a}\\ &=-\frac{2 g \sqrt{g \cos (e+f x)}}{a f}-\frac{\operatorname{Subst}\left (\int \frac{x^{3/2}}{1-\frac{x^2}{g^2}} \, dx,x,g \cos (e+f x)\right )}{a f g}-\frac{g^2 \int \frac{b+a \sin (e+f x)}{\sqrt{g \cos (e+f x)} (a+b \sin (e+f x))} \, dx}{a}\\ &=-\frac{g \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (1-\frac{x^2}{g^2}\right )} \, dx,x,g \cos (e+f x)\right )}{a f}-\frac{g^2 \int \frac{1}{\sqrt{g \cos (e+f x)}} \, dx}{b}-\frac{\left (\left (-a^2+b^2\right ) g^2\right ) \int \frac{1}{\sqrt{g \cos (e+f x)} (a+b \sin (e+f x))} \, dx}{a b}\\ &=-\frac{(2 g) \operatorname{Subst}\left (\int \frac{1}{1-\frac{x^4}{g^2}} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}+\frac{\left (\sqrt{-a^2+b^2} g^2\right ) \int \frac{1}{\sqrt{g \cos (e+f x)} \left (\sqrt{-a^2+b^2}-b \cos (e+f x)\right )} \, dx}{2 b}+\frac{\left (\sqrt{-a^2+b^2} g^2\right ) \int \frac{1}{\sqrt{g \cos (e+f x)} \left (\sqrt{-a^2+b^2}+b \cos (e+f x)\right )} \, dx}{2 b}+\frac{\left (\left (a^2-b^2\right ) g^3\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \left (\left (a^2-b^2\right ) g^2+b^2 x^2\right )} \, dx,x,g \cos (e+f x)\right )}{a f}-\frac{\left (g^2 \sqrt{\cos (e+f x)}\right ) \int \frac{1}{\sqrt{\cos (e+f x)}} \, dx}{b \sqrt{g \cos (e+f x)}}\\ &=-\frac{2 g^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \sqrt{g \cos (e+f x)}}-\frac{g^2 \operatorname{Subst}\left (\int \frac{1}{g-x^2} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}-\frac{g^2 \operatorname{Subst}\left (\int \frac{1}{g+x^2} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}+\frac{\left (2 \left (a^2-b^2\right ) g^3\right ) \operatorname{Subst}\left (\int \frac{1}{\left (a^2-b^2\right ) g^2+b^2 x^4} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}+\frac{\left (\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)}\right ) \int \frac{1}{\sqrt{\cos (e+f x)} \left (\sqrt{-a^2+b^2}-b \cos (e+f x)\right )} \, dx}{2 b \sqrt{g \cos (e+f x)}}+\frac{\left (\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)}\right ) \int \frac{1}{\sqrt{\cos (e+f x)} \left (\sqrt{-a^2+b^2}+b \cos (e+f x)\right )} \, dx}{2 b \sqrt{g \cos (e+f x)}}\\ &=-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{g^{3/2} \tanh ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}-\frac{2 g^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \sqrt{g \cos (e+f x)}}-\frac{\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b \left (b-\sqrt{-a^2+b^2}\right ) f \sqrt{g \cos (e+f x)}}+\frac{\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b \left (b+\sqrt{-a^2+b^2}\right ) f \sqrt{g \cos (e+f x)}}+\frac{\left (\sqrt{-a^2+b^2} g^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} g-b x^2} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}+\frac{\left (\sqrt{-a^2+b^2} g^2\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} g+b x^2} \, dx,x,\sqrt{g \cos (e+f x)}\right )}{a f}\\ &=-\frac{g^{3/2} \tan ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}+\frac{\sqrt [4]{-a^2+b^2} g^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt{g}}\right )}{a \sqrt{b} f}-\frac{g^{3/2} \tanh ^{-1}\left (\frac{\sqrt{g \cos (e+f x)}}{\sqrt{g}}\right )}{a f}+\frac{\sqrt [4]{-a^2+b^2} g^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{g \cos (e+f x)}}{\sqrt [4]{-a^2+b^2} \sqrt{g}}\right )}{a \sqrt{b} f}-\frac{2 g^2 \sqrt{\cos (e+f x)} F\left (\left .\frac{1}{2} (e+f x)\right |2\right )}{b f \sqrt{g \cos (e+f x)}}-\frac{\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b \left (b-\sqrt{-a^2+b^2}\right ) f \sqrt{g \cos (e+f x)}}+\frac{\sqrt{-a^2+b^2} g^2 \sqrt{\cos (e+f x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (e+f x)\right |2\right )}{b \left (b+\sqrt{-a^2+b^2}\right ) f \sqrt{g \cos (e+f x)}}\\ \end{align*}
Mathematica [C] time = 5.30359, size = 484, normalized size = 1.1 \[ \frac{\csc (e+f x) (g \cos (e+f x))^{3/2} \left (a+b \sqrt{\sin ^2(e+f x)}\right ) \left (8 a b^{3/2} \cos ^{\frac{5}{2}}(e+f x) F_1\left (\frac{5}{4};\frac{1}{2},1;\frac{9}{4};\cos ^2(e+f x),\frac{b^2 \cos ^2(e+f x)}{b^2-a^2}\right )-5 \left (a^2-b^2\right ) \left (\sqrt{2} \sqrt [4]{a^2-b^2} \log \left (-\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (e+f x)}+\sqrt{a^2-b^2}+b \cos (e+f x)\right )-\sqrt{2} \sqrt [4]{a^2-b^2} \log \left (\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (e+f x)}+\sqrt{a^2-b^2}+b \cos (e+f x)\right )+2 \sqrt{2} \sqrt [4]{a^2-b^2} \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (e+f x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \sqrt{2} \sqrt [4]{a^2-b^2} \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (e+f x)}}{\sqrt [4]{a^2-b^2}}+1\right )-2 \sqrt{b} \log \left (1-\sqrt{\cos (e+f x)}\right )+2 \sqrt{b} \log \left (\sqrt{\cos (e+f x)}+1\right )+4 \sqrt{b} \tan ^{-1}\left (\sqrt{\cos (e+f x)}\right )\right )\right )}{20 a \sqrt{b} f \left (a^2-b^2\right ) \cos ^{\frac{3}{2}}(e+f x) (a \csc (e+f x)+b)} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 2.729, size = 216, normalized size = 0.5 \begin{align*} -{\frac{1}{2\,af}{g}^{{\frac{3}{2}}}\ln \left ( 2\,{\frac{\sqrt{g}\sqrt{-2\, \left ( \sin \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}g+g}+2\,g\cos \left ( 1/2\,fx+e/2 \right ) -g}{-1+\cos \left ( 1/2\,fx+e/2 \right ) }} \right ) }-{\frac{1}{2\,af}{g}^{{\frac{3}{2}}}\ln \left ( 2\,{\frac{\sqrt{g}\sqrt{-2\, \left ( \sin \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}g+g}-2\,g\cos \left ( 1/2\,fx+e/2 \right ) -g}{\cos \left ( 1/2\,fx+e/2 \right ) +1}} \right ) }+2\,{\frac{g\sqrt{-2\, \left ( \sin \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}g+g}}{af}}+{\frac{{g}^{2}}{af}\ln \left ( 2\,{\frac{\sqrt{-g}\sqrt{-2\, \left ( \sin \left ( 1/2\,fx+e/2 \right ) \right ) ^{2}g+g}-g}{\cos \left ( 1/2\,fx+e/2 \right ) }} \right ){\frac{1}{\sqrt{-g}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}} \csc \left (f x + e\right )}{b \sin \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (g \cos \left (f x + e\right )\right )^{\frac{3}{2}} \csc \left (f x + e\right )}{b \sin \left (f x + e\right ) + a}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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